Answer
a) 0
b) $2.7\times10^{-3}T.m^{2}$
c) $4.5\times10^{-3}T.m^{2}$
Work Step by Step
$A=0.015m^{2}$ and $B=0.3T$
a) Loop's plane parallel to the field, $\theta=90^{\circ}$,
flux = $BAcos\theta=0$
b) Loop's plane makes angle of $37^{\circ}$ to field, $\theta=53^{\circ}$,
flux = $BAcos53^{\circ}=2.7\times10^{-3}T.m^{2}$
c) Loop's plane is perpendicular to the field, $\theta=0$,
flux = $BAcos0^{\circ}=4.5\times10^{-3}T.m^{2}$
