## College Physics (7th Edition)

Since , $R=\frac{V^{2}}{P}$, the 60-W bulb has higher resistance than the 100-W bulb. When these are in series, they have the same current. Thus, the 60-W bulb will have higher voltage. Thus, the 60-W bulb has more power because $P=IV$.
Since , $R=\frac{V^{2}}{P}$, the 60-W bulb has higher resistance than the 100-W bulb. When these are in series, they have the same current. Thus, the 60-W bulb will have higher voltage. Thus, the 60-W bulb has more power because $P=IV$.