Answer
(a) 1.5 C passing a given point in 1.5 min
Work Step by Step
Current $I=\frac{q}{t}$
In situation (a),
$I=\frac{1.5\,C}{1.5\times60\,s}=0.017\,A$
In situation (b),
$I=\frac{3.0\,C}{1.0\times60\,s}=0.050\,A$
In situation (c),
$I=\frac{0.5\,C}{0.10\times60\,s}=0.08\,A$
Situation (a) involves the least current.