College Physics (7th Edition)

$2.0\times10^{5}N/C$
E=$\frac{F}{q}$(F is the magnitude of force and q is the charge of the electron) $= \frac{3.2\times10^{-14}N}{1.602\times10^{-19}C}\approx 2.0\times10^{5}N/C.^{\circ}$