College Physics (7th Edition)

Published by Pearson
ISBN 10: 0-32160-183-1
ISBN 13: 978-0-32160-183-4

Chapter 10 - Temperature and Kinetic Theory - Learning Path Questions and Exercises - Multiple Choice Questions - Page 380: 14


(b) $\frac{5}{2}nRT$

Work Step by Step

Since at room temperature, vibrational energy is not active, only translation and rotation energy will contribute to internal energy. So, Internal energy is addition of $\frac{3}{2}nRT$ (translation energy) and $1nRT$ (rotational energy), which makes it $\frac{5}{2}nRT$.
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