College Physics (7th Edition)

Published by Pearson
ISBN 10: 0-32160-183-1
ISBN 13: 978-0-32160-183-4

Chapter 1 - Measurement and Problem Solving - Learning Path Questions and Exercises - Exercises - Page 31: 68


$a). less\, than \,13\, miles. $ $b). 6.058\, miles$

Work Step by Step

a). The distance travelled due North is less than 13 miles. Because the angle created is $25^{\circ}$. Had it been more than $45^{\circ}$ then it would have been more than 13 miles. And at 45 degrees it would have been equal to 13 miles. b).If d is the distance travelled due N, then $\frac{d}{13}= tan25^{\circ}=0.466$ $d=13\times 0.466=6.058\,miles.$
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