College Physics (7th Edition)

Published by Pearson
ISBN 10: 0-32160-183-1
ISBN 13: 978-0-32160-183-4

Chapter 1 - Measurement and Problem Solving - Learning Path Questions and Exercises - Exercises - Page 31: 59

Answer

$5.5 \times 10^{3} kg/m^{3}$

Work Step by Step

Mass of earth $= 5.98 \times 10^{24} kg $ Radius of earth $= 6400 km = 6.4 \times 10^{6} m$ Volume $= \frac{4}{3} \times \frac{22}{7} \times radius^{3}=1.1 \times 10^{21} m^{3} $ Thus, Density $ = \frac{5.98 \times 10^{24}}{1.1\times 10^{21}}=5.5\times 10^{3} kg/m^{3}$
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