College Physics (7th Edition)

Published by Pearson
ISBN 10: 0-32160-183-1
ISBN 13: 978-0-32160-183-4

Appendix I - C Geometric Relationships - Circumference (c), Area (A), and Volume(V) - Appendix I-C Exercises On Geometric Relationships - Page A-4: 2

Answer

$19.64cm^{2}$

Work Step by Step

Since the side length is 5 cms, radius = 2.5 cms. Thus, area of end of the rod = $\frac{22}{7}\times2.5^{2}cm^{2}=19.64cm^{2}$
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