College Physics (7th Edition)

Published by Pearson
ISBN 10: 0-32160-183-1
ISBN 13: 978-0-32160-183-4

Appendix I - C Geometric Relationships - Circumference (c), Area (A), and Volume(V) - Appendix I-C Exercises On Geometric Relationships - Page A-4: 1

Answer

a). On the order of $1.4\times10^{4} cm^{3}$ b). On the order of $ 900 \,in^{3}$

Work Step by Step

Volume= $\frac{4}{3}\times\frac{22}{7}\times r^{3}$ Radius of bowling ball can be approx 6 inches $\approx$ 15 cms a). V= $\frac{4}{3}\times\frac{22}{7}\times 15^{3}=1.4\times10^{4} cm^{3}$ b). V= $\frac{4}{3}\times\frac{22}{7}\times 6^{3}=900 \,in^{3}$
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