Answer
a). On the order of $1.4\times10^{4} cm^{3}$
b). On the order of $ 900 \,in^{3}$
Work Step by Step
Volume= $\frac{4}{3}\times\frac{22}{7}\times r^{3}$
Radius of bowling ball can be approx 6 inches $\approx$ 15 cms
a). V= $\frac{4}{3}\times\frac{22}{7}\times 15^{3}=1.4\times10^{4} cm^{3}$
b). V= $\frac{4}{3}\times\frac{22}{7}\times 6^{3}=900 \,in^{3}$