## College Physics (4th Edition)

The initial speed of the plate should be $2.76~m/s$
We can find the rate of deceleration of the plate is it slides: $mg~\mu_k = ma$ $a = g~\mu_k$ $a = (9.80~m/s^2)(0.32)$ $a = 3.136~m/s^2$ Note that the plate's acceleration as it slides is $-3.136~m/s^2$. We can find the initial speed: $v_f^2 = v_0^2+2ax$ $v_0^2 = v_f^2-2ax$ $v_0 = \sqrt{v_f^2-2ax}$ $v_0 = \sqrt{0-(2)(-3.136~m/s^2)(0.44~m)}$ $v_0 = 2.76~m/s$ The initial speed of the plate should be $2.76~m/s$