College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Review & Synthesis: Chapters 1-5 - Review Exercises - Page 192: 1

Answer

The units for the spring constant $k$ are: $\frac{kg}{s^2}$

Work Step by Step

The units for force are newtons which in base units are $\frac{kg~m}{s^2}$ In dimensions, we can represent this as: $[M][L][T]^{-2}$, where $M$ is mass, $[L]$ is length, and $[T]$ is time. The dimensions for the distance $x$ are $[L]$ Let $D$ be the dimensions for the spring constant $k$. Using the equation $F = kx$, we can find the dimensions for the spring constant $k$: $[M][L][T]^{-2} = D~([L])$ $D = [M][T]^{-2}$ The dimensions for the spring constant $k$ are $[M][T]^{-2}$, which means that the units are: $\frac{kg}{s^2}$
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