College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 9 - Problems - Page 362: 47

Answer

The speed of the water through the nozzle is $50~m/s$

Work Step by Step

We can find the speed that the water moves through the nozzle: $A_2~v_2 = A_1~v_1$ $v_2 = \frac{A_1~v_1}{A_2}$ $v_2 = \frac{\pi~r_1^2~v_1}{\pi~r_2^2}$ $v_2 = \frac{r_1^2~v_1}{r_2^2}$ $v_2 = \frac{(0.010~m)^2~(2.0~m/s)}{(0.0020~m)^2}$ $v_2 = 50~m/s$ The speed of the water through the nozzle is $50~m/s$.
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