Answer
(a) $21,300~Pa$
(b) $3.09~lb/in^2$
(c) $0.21~atm$
(d) $160~torr$
Work Step by Step
(a) We can convert 160 mm Hg to units of Pa:
$160~mm~Hg \times \frac{133.3~Pa}{1~mm~Hg} = 21,300~Pa$
(b) We can convert 160 mm Hg to units of $lb/in^2$:
$160~mm~Hg \times \frac{1~lb/in^2}{51.7~mm~Hg} = 3.09~lb/in^2$
(c) We can convert 160 mm Hg to units of atm:
$160~mm~Hg \times \frac{1~atm}{760~mm~Hg} = 0.21~atm$
(d) We can convert 160 mm Hg to units of torr:
$160~mm~Hg \times \frac{1.0~torr}{1~mm~Hg} = 160~torr$
