College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 8 - Problems - Page 312: 26


The work done on the stone is $151~J$

Work Step by Step

We can find the work done on the stone: $Work = \tau ~\Delta \theta$ $Work = r~F ~\Delta \theta$ $Work = (0.10~m)(20.0~N)(12~rev)(2\pi~rad/rev)$ $Work = 151~J$ The work done on the stone is $151~J$.
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