## College Physics (4th Edition)

The total momentum of the ship and the crew is $~5.0\times 10^9~kg~m/s$
We can find the magnitude of the total momentum of the ship and the crew: $p = m~v$ $p = (2.0\times 10^3~kg+4.8\times 10^4~kg)~(1.0\times 10^5~m/s)$ $p = (5.0\times 10^4~kg)~(1.0\times 10^5~m/s)$ $p = 5.0\times 10^9~kg~m/s$ The total momentum of the ship and the crew is $~5.0\times 10^9~kg~m/s$.