College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 7 - Problems - Page 267: 81

Answer

The velocity of the center of mass of the system is $37.4~m/s$

Work Step by Step

We can find the velocity of the center of mass of the system: $v_{com} = \frac{m_1~v_1+m_2~v_2+m_3~v_3}{m_1+m_2+m_3}$ $v_{com} = \frac{(3.0~kg)(290~m/s)+(5.0~kg)(-120~m/s)+(2.0~kg)(52~m/s)}{3.0~kg+5.0~kg+2.0~kg}$ $v_{com} = 37.4~m/s$ The velocity of the center of mass of the system is $37.4~m/s$.
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