College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 7 - Problems - Page 266: 65


$v_{2f} = 1.73~v_{1f}$

Work Step by Step

Let $M$ be the mass of each puck. Before the collision, the y-component of momentum is zero. By conservation of momentum, the y-component of momentum must also be zero after the collision. After the collision, the magnitude of the y-component of momentum of each puck must be equal. We can find the $v_{2f}$ in terms of $v_{1f}$: $M~v_{2f}~sin~30.0^{\circ} = M~v_{1f}~sin~60.0^{\circ}$ $v_{2f} = \frac{(v_{1f})~(sin~60.0^{\circ})}{sin~30.0^{\circ}}$ $v_{2f} = 1.73~v_{1f}$
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