College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 7 - Problems - Page 266: 56


The mass of block B is $0.20~kg$

Work Step by Step

Let $v_A$ be the speed of block A and let $v_B$ be the speed of block B. Since block B travels 3.0 meters in the same time it takes block A to travel 1.0 meter, then $v_B = 3~v_A$. By conservation of momentum, block A's momentum is equal in magnitude to block B's momentum. We can find the mass of block B: $m_B~v_B = m_A~v_A$ $m_B = \frac{m_A~v_A}{v_B}$ $m_B = \frac{m_A~v_A}{3~v_A}$ $m_B = \frac{m_A}{3}$ $m_B = \frac{0.60~kg}{3}$ $m_B = 0.20~kg$ The mass of block B is $0.20~kg$
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