College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 6 - Problems - Page 231: 73

Answer

It will take a minimum time of 245 seconds to do this work.

Work Step by Step

We can find the total amount of work the man must do: $Work = 50\times mgh = (50)(10.0~kg)(9.80~m/s^2)(2.00~m) = 9800~J$ We can find the time it takes to do this work: $t = \frac{Energy}{Power} = \frac{9800~J}{40.0~W} = 245~s$ It will take a minimum time of 245 seconds to do this work.
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