## College Physics (4th Edition)

The minimum spring constant of the bungee cord is $113~N/m$
Jorge needs to stop a distance of 53.0 meters below his starting point. Thus the bungee cord needs to stretch a distance of 26.0 meters. The change in gravitational potential energy will be equal in magnitude to the elastic potential energy stored in the bungee cord at the bottom of the jump: $\frac{1}{2}kx^2 = mgh$ $k = \frac{2mgh}{x^2}$ $k = \frac{(2)(75.0~kg)(9.80~m/s^2)(53.0~m)}{(26.0~m)^2}$ $k = 113~N/m$ The minimum spring constant of the bungee cord is $113~N/m$.