## College Physics (4th Edition)

(a) The radial acceleration is $79~m/s^2$ (b) The tension in the cord is $39.5~N$
(a) We can find the radial acceleration: $a_r = \frac{v^2}{r}$ $a_r = \frac{(2.0\pi~m/s)^2}{0.50~m}$ $a_r = 79~m/s^2$ The radial acceleration is $79~m/s^2$ (b) We can find the tension in the cord: $T = m~a_r$ $T = (0.50~kg)(79~m/s^2)$ $T = 39.5~N$ The tension in the cord is $39.5~N$