College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 5 - Problems - Page 190: 78


(a) The radial acceleration is $79~m/s^2$ (b) The tension in the cord is $39.5~N$

Work Step by Step

(a) We can find the radial acceleration: $a_r = \frac{v^2}{r}$ $a_r = \frac{(2.0\pi~m/s)^2}{0.50~m}$ $a_r = 79~m/s^2$ The radial acceleration is $79~m/s^2$ (b) We can find the tension in the cord: $T = m~a_r$ $T = (0.50~kg)(79~m/s^2)$ $T = 39.5~N$ The tension in the cord is $39.5~N$
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