College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 5 - Problems - Page 189: 74

Answer

(a) At $t = 376.8~s$, the jogger's velocity is $3.0~m/s$ toward the east. (b) At $t = 94.2~s$, the jogger's velocity is $3.0~m/s$ toward the west.

Work Step by Step

(a) We can find the jogger's speed: $v = \frac{d}{t} = \frac{(2\pi)(90.0~m)}{188.4~s} = 3.0~m/s$ At $t = 376.8~s$, the jogger will be completing the second revolution, so the direction will be the same as the direction at $t=0$. Therefore, at $t = 376.8~s$, the jogger's velocity is $3.0~m/s$ toward the east. (b) At $t = 94.2~s$, the jogger will be halfway through the first revolution, so the direction will be the opposite as the direction at $t=0$. Therefore, at $t = 94.2~s$, the jogger's velocity is $3.0~m/s$ toward the west.
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