College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 5 - Problems - Page 189: 66

Answer

The satellite should be placed a distance of $20,400~km$ from the center of the planet.

Work Step by Step

When a satellite orbits a planet, the gravitational force provides the centripetal force to keep the satellite moving in a circle. Let $M_p$ be the mass of the planet and let $M_s$ be the mass of the satellite. We can find an expression for the angular speed of a satellite: $\frac{G~M_p~M_s}{R^2} = M_s~\omega^2~R$ $\omega = \sqrt{\frac{G~M_p}{R^3}}$ We can find an expression for a satellite's orbital period $P$: $P = \frac{2\pi}{\omega} = 2\pi~\sqrt{\frac{R^3}{G~M_p}}$ We can find use the expression for a satellite's orbital period $P$ to find the orbital radius $R$: $P = 2\pi~\sqrt{\frac{R^3}{G~M_p}}$ $R = (\frac{P^2~G~M_p}{4\pi^2})^{1/3}$ $R = [~\frac{(88,620~s)^2~(6.67\times 10^{-11}~m^3/kg~s^2)~(6.42\times 10^{23}~kg)}{4\pi^2}~~]^{1/3}$ $R = 20,423,094~m$ $R = 20,400~km$ The satellite should be placed a distance of $20,400~km$ from the center of the planet.
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