## College Physics (4th Edition)

The fastest speed that the car can go over the hill without losing contact with the ground is $23.2~m/s$
To find the maximum speed, we can assume that the normal force is zero, and the gravitational force provides the centripetal force to keep the car moving in a circular path. Then the radial acceleration is $g$: $\frac{v^2}{r} = g$ $v = \sqrt{g~r}$ $v = \sqrt{(9.80~m/s^2)(55.0~m)}$ $v = 23.2~m/s$ The fastest speed that the car can go over the hill without losing contact with the ground is $23.2~m/s$.