College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 5 - Problems - Page 187: 46


The angular acceleration is $190~rad/s^2$

Work Step by Step

We can express the angular velocity in units of $rad/s$: $\omega = 7200~rpm \times \frac{2\pi~rad}{1~rev} \times \frac{1~min}{60~s} = 240\pi~rad/s$ We can find the angular acceleration $\alpha$: $\omega_f = \omega_0+\alpha~t$ $\alpha = \frac{\omega_f - \omega_0}{t}$ $\alpha = \frac{240\pi~rad/s - 0}{4.0~s}$ $\alpha = 190~rad/s^2$ The angular acceleration is $190~rad/s^2$
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