College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 4 - Multiple-Choice Questions - Page 147: 15


The correct answer is: (a) Projectile launched at $60^{\circ}$

Work Step by Step

The correct answer is: (a) Projectile launched at $60^{\circ}$ Let $v_0$ be the initial velocity. The time to reach maximum height is $t = \frac{v_0~sin~\theta}{g}$. The total time of flight is $2t = \frac{2~v_0~sin~\theta}{g}$ Since $sin~60^{\circ} \gt sin~30^{\circ}$, the projectile launched at an angle of $60^{\circ}$ has a longer time of flight.
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