Answer
The correct answer is:
(e) $896~N$
Work Step by Step
The correct answer is:
(e) $896~N$
If the elevator is slowing down while descending then the elevator is accelerating upward at a rate of $3.00~m/s^2$. We can find the normal force of the scale pushing upward on the person:
$F_N-mg = m~a$
$F_N = m~(g+a)$
$F_N = (70.0~kg)(9.80~m/s^2+3.00~m/s^2)$
$F_N = 896~N$
