College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 4 - Multiple-Choice Questions - Page 147: 13


The correct answer is: (e) $896~N$

Work Step by Step

The correct answer is: (e) $896~N$ If the elevator is slowing down while descending then the elevator is accelerating upward at a rate of $3.00~m/s^2$. We can find the normal force of the scale pushing upward on the person: $F_N-mg = m~a$ $F_N = m~(g+a)$ $F_N = (70.0~kg)(9.80~m/s^2+3.00~m/s^2)$ $F_N = 896~N$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.