## College Physics (4th Edition)

The magnitude of the force exerted by the locomotive on the caboose is $3.5~N$
The caboose accelerates at $3.0~m/s^2$. We can find the net force on the caboose: $\sum F = ma = (1.0~kg)(3.0~m/s^2) = 3.0~N$ We can find the force $F_l$ exerted on the caboose by the locomotive: $F_l-F_f = \sum F$ $F_l = \sum F+F_f$ $F_l = 3.0~N+0.50~N$ $F_l = 3.5~N$ The magnitude of the force exerted by the locomotive on the caboose is $3.5~N$