College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 3 - Problems - Page 114: 57

Answer

We can rank the objects by their speeds, from largest to smallest: $c = d \gt a = b = e$

Work Step by Step

(a) $F=ma$ $a = \frac{F}{m}$ $v_a = 0+at_1 = \frac{F~t_1}{m}$ (b) $2F=(2m)~a$ $a = \frac{2F}{2m} = \frac{F}{m}$ $v_b = 0+at_1 = \frac{F~t_1}{m}$ (c) $F=ma$ $a = \frac{F}{m}$ $v_c = 0+a~(2t_1) = \frac{2F~t_1}{m}$ (d) $2F=ma$ $a = \frac{2F}{m}$ $v_d = 0+at_1 = \frac{2F~t_1}{m}$ (e) $F=(2m)a$ $a = \frac{F}{2m}$ $v_e = 0+a~(2t_1) = \frac{F~(2t_1)}{2m} = \frac{F~t_1}{m}$ We can rank the objects by their speeds, from largest to smallest: $c = d \gt a = b = e$
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