## College Physics (4th Edition)

The average forward force on the airplane is $4800~N$
We can find the acceleration: $v_f = v_0+at$ $a = \frac{v_f-v_0}{t}$ $a = \frac{35~m/s-0}{8.0~s}$ $a = 4.375~m/s^2$ We can find the average forward force on the airplane: $F = ma = (1100~kg)(4.375~m/s^2) = 4800~N$ The average forward force on the airplane is $4800~N$