College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 3 - Problems - Page 113: 37

Answer

(a) $t = 12.9~s$ (b) $m = 45.9~kg$

Work Step by Step

(a) $v_f = v_0+at$ $t = \frac{v_f-v_0}{a}$ $t = \frac{22~m/s-0}{1.7~m/s^2}$ $t = 12.9~s$ (b) $F=ma$ $m = \frac{F}{a}$ $m = \frac{78~N}{1.7~m/s^2}$ $m = 45.9~kg$
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