## College Physics (4th Edition)

$v = 1420~m/s$
We can find the required speed: $\lambda = \frac{h}{mv}$ $v = \frac{h}{m~\lambda}$ $v = \frac{6.626\times 10^{-34}~J~s}{(1.67\times 10^{-27}~kg)(0.28\times 10^{-9}~m)}$ $v = 1420~m/s$