College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 28 - Problems - Page 1074: 6


$v = 1420~m/s$

Work Step by Step

We can find the required speed: $\lambda = \frac{h}{mv}$ $v = \frac{h}{m~\lambda}$ $v = \frac{6.626\times 10^{-34}~J~s}{(1.67\times 10^{-27}~kg)(0.28\times 10^{-9}~m)}$ $v = 1420~m/s$
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