College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 28 - Problems - Page 1074: 4


$p = 1.7\times 10^{-24}~kg~m/s$

Work Step by Step

We can find the momentum: $\lambda = \frac{h}{p}$ $p = \frac{h}{\lambda}$ $p = \frac{6.626\times 10^{-34}~J~s}{0.40\times 10^{-9}~m}$ $p = 1.7\times 10^{-24}~kg~m/s$
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