College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 27 - Problems - Page 1041: 4


The minimum required energy is $6.89\times 10^{-19}~J$

Work Step by Step

We can find the minimum required energy: $E = h~f$ $E = (6.626\times 10^{-34}~J~s)(1.04\times 10^{15}~Hz)$ $E = 6.89\times 10^{-19}~J$ The minimum required energy is $6.89\times 10^{-19}~J$
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