## College Physics (4th Edition)

$E = 1326~MeV$
We can find the total energy $E$: $E^2 = E_0^2+(pc)^2$ $E^2 = (939.6~MeV)^2+[(935~MeV/c)(c)]^2$ $E^2 = (939.6~MeV)^2+(935~MeV)^2$ $E^2 = 1757073.16~(MeV)^2$ $E = \sqrt{1757073.16~(MeV)^2}$ $E = 1326~MeV$