## College Physics (4th Edition)

Let $L_0 = 35.2~m$. The contracted length is $L = 30.5~m$. We can find $\gamma$: $L = \frac{L_0}{\gamma}$ $\gamma = \frac{L_0}{L}$ $\gamma = \frac{35.2~m}{30.5~m}$ $\gamma = 1.154$ Let $\Delta t_0 = 22.2~min$. We can find $\Delta t$: $\Delta t = \gamma~\Delta t_0$ $\Delta t = (1.154)(22.2~min)$ $\Delta t = 25.4~min$ The astronaut would say that she exercises for 25.4 minutes.