College Physics (4th Edition)

Let $\Delta t_0$ be the half-life measured by an observer moving with the asteroid. $T = \frac{\Delta t_0}{\sqrt{1-\frac{v^2}{c^2}}}$ $\Delta t_0 = T~\sqrt{1-\frac{v^2}{c^2}} \lt T$ The correct answer is: (a) less than T