## College Physics (4th Edition)

Let $\Delta t_0 = 1~s$. We can find the time between ticks measured by the observer: $\Delta t = \frac{\Delta t_0}{\sqrt{1-\frac{v^2}{c^2}}} \gt \Delta t_0$ Let $L_0 = 10~cm$. We can find the length measured by the observer: $L = L_0~\sqrt{1-\frac{v^2}{c^2}} \lt L_0$ The correct answer is: (c) more than 1 s; less than 10 cm