Answer
The correct answer is:
(c) more than 1 s; less than 10 cm
Work Step by Step
Let $\Delta t_0 = 1~s$. We can find the time between ticks measured by the observer:
$\Delta t = \frac{\Delta t_0}{\sqrt{1-\frac{v^2}{c^2}}} \gt \Delta t_0$
Let $L_0 = 10~cm$. We can find the length measured by the observer:
$L = L_0~\sqrt{1-\frac{v^2}{c^2}} \lt L_0$
The correct answer is:
(c) more than 1 s; less than 10 cm
