## College Physics (4th Edition)

Published by McGraw-Hill Education

# Chapter 26 - Multiple-Choice Questions - Page 1009: 6

#### Answer

The correct answer is: (c) more than 1 s; less than 10 cm

#### Work Step by Step

Let $\Delta t_0 = 1~s$. We can find the time between ticks measured by the observer: $\Delta t = \frac{\Delta t_0}{\sqrt{1-\frac{v^2}{c^2}}} \gt \Delta t_0$ Let $L_0 = 10~cm$. We can find the length measured by the observer: $L = L_0~\sqrt{1-\frac{v^2}{c^2}} \lt L_0$ The correct answer is: (c) more than 1 s; less than 10 cm

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