College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 22 - Problems - Page 864: 33


$E_{rms} = 258~V/m$

Work Step by Step

We can find the intensity of the laser: $I = \frac{P}{A}$ $I = \frac{P}{\pi~r^2}$ $I = \frac{10.0\times 10^{-3}~W}{(\pi)~(4.25\times 10^{-3}~m)^2}$ $I = 176.2~W/m^2$ We can find $E_{rms}$: $E_{rms}^2 = \frac{I}{c~\epsilon_0}$ $E_{rms} = \sqrt{\frac{I}{c~\epsilon_0}}$ $E_{rms} = \sqrt{\frac{176.2~W/m^2}{(3.0\times 10^8~m/s)~(8.85\times 10^{-12}~C^2/N~m^2)}}$ $E_{rms} = 258~V/m$
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