## College Physics (4th Edition)

(a) The wave is traveling in the +y-direction. (b) $B_x = \frac{E_m}{c}~sin~(ky+\omega t+\frac{\pi}{6})$ $B_y = 0$ $B_z = 0$
(a) From the term $ky-\omega t$, we can see that the wave is traveling in the +y-direction. (b) Since the direction of propagation is determined by the cross-product $E\times B$, by the right-hand rule, the magnetic field must be pointing in the +x-direction at y = 0 and t = 0. Note that $(+z)\times (+x) = +y$ We can find the components of the magnetic field of this wave: $B_x = \frac{E_m}{c}~sin~(ky+\omega t+\frac{\pi}{6})$ $B_y = 0$ $B_z = 0$