## College Physics (4th Edition)

$\omega = 390~rad/s$
We can find the angular speed as: $emf = \omega~NBA$ $\omega = \frac{emf}{NBA}$ $\omega = \frac{17.0~V}{(80)(0.45~T)(0.020~m)(0.060~m)}$ $\omega = 390~rad/s$