## College Physics (4th Edition)

The amplitude of the induced $emf$ is $18.0~V$
We can write an expression for the induced $emf$: $emf = \omega~NBA~\vert sin~(\omega~t) \vert$ We can write an expression for the amplitude of the induced $emf$ when $\omega = 15.0~rad/s$: $emf_1 = (15.0~rad/s)~NBA = 27.0~V$ We can find the induced $emf$ when $\omega = 10.0~rad/s$: $emf_2 = (10.0~rad/s)~NBA$ $emf_2 = \frac{10.0~rad/s}{15.0~rad/s}~emf_1$ $emf_2 = (\frac{2}{3})~(27.0~V)$ $emf_2 = 18.0~V$ The amplitude of the induced $emf$ is $18.0~V$.