College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 2 - Problems: 39

Answer

The net force is 2 kN directed to the east.

Work Step by Step

We can find the magnitude of each component of the net force $F$: $F_x = 7~kN - 5~kN = 2~kN$ directed to the east $F_y = 52~kN - 52~kN = 0$ The net force is 2 kN directed to the east.
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