Answer
The net force is 2 kN directed to the east.
Work Step by Step
We can find the magnitude of each component of the net force $F$:
$F_x = 7~kN - 5~kN = 2~kN$ directed to the east
$F_y = 52~kN - 52~kN = 0$
The net force is 2 kN directed to the east.
