College Physics (4th Edition)

Published by McGraw-Hill Education

Chapter 2 - Problems - Page 66: 38

Answer

(a) The magnitude of the net force is 30 N directed to the right. (b) The magnitude of the net force is zero. (c) The magnitude of the net force is 18 N directed downward.

Work Step by Step

(a) We can find the magnitude of the net force $F$: $F = 40~N - 10~N = 30~N$ (directed to the right) The magnitude of the net force is 30 N directed to the right. (b) We can find the magnitude of each component of the net force $F$: $F_x = 10~N - 10~N = 0$ $F_y = 18~N - 18~N = 0$ The magnitude of the net force is zero. (c) We can find the magnitude of each component of the net force $F$: $F_x = 10~N - 10~N = 0$ $F_y = 18~N$ directed downward The magnitude of the net force is 18 N directed downward.

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