College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 2 - Problems: 6

Answer

$B = C \lt A$

Work Step by Step

$A_x = 4$ $A_y = 4$ $B_x = -1$ $B_y = 3$ $C_x = 1$ $C_y = -3$ We can find the magnitude of each vector: The magnitude of vector A is $\sqrt{(4)^2+(4)^2}$ which is 5.66 The magnitude of vector B is $\sqrt{(-1)^2+(3)^2}$ which is 3.16 The magnitude of vector C is $\sqrt{(1)^2+(-3)^2}$ which is 3.16 We can rank the vectors in order of increasing magnitude: $B = C \lt A$
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