College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 2 - Problems: 11

Answer

$F \lt E \lt D$

Work Step by Step

$D_x = 3$ $D_y = 4$ $E_x = 2$ $E_y = -4$ $F_x = 2$ $F_y = 0$ We can find the magnitude of each vector: The magnitude of vector D is $\sqrt{(3)^2+(4)^2}$ which is 5.0 The magnitude of vector E is $\sqrt{(2)^2+(-4)^2}$ which is 4.5 The magnitude of vector F is $\sqrt{(2)^2+(0)^2}$ which is 2.0 We can rank the vectors in order of increasing magnitude: $F \lt E \lt D$
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