College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 19 - Problems - Page 757: 80


$I = 39~A$

Work Step by Step

We can find the current $I$ in the solenoid: $B = \mu~n~I$ $I = \frac{B}{\mu~n}$ $I = \frac{(0.24~T)}{(4\pi \times 10^{-7}~T~m/A)(4850~m^{-1})}$ $I = 39~A$
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