College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 19 - Problems - Page 757: 75


$B = 5.4\times 10^{-3}~T$

Work Step by Step

We can find the magnetic field in the solenoid: $B = \frac{\mu~N~I}{L}$ $B = \frac{(4\pi \times 10^{-7}~T~m/A)(244)(4.5~A)}{0.256~m}$ $B = 5.4\times 10^{-3}~T$
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