## College Physics (4th Edition)

$F = 2.4 \times 10^{-12}~N$ (directed vertically upward)
We can find the magnetic force: $F = q~v\times B$ $F = (1.6\times 10^{-19}~C)(6.0 \times 10^6~m/s)(2.50~T)$ $F = 2.4 \times 10^{-12}~N$ By the right hand rule, $v \times B$ is directed vertically upward.