College Physics (4th Edition)

Published by McGraw-Hill Education
ISBN 10: 0073512141
ISBN 13: 978-0-07351-214-3

Chapter 19 - Problems - Page 752: 9


$F = 2.4 \times 10^{-12}~N$ (directed vertically upward)

Work Step by Step

We can find the magnetic force: $F = q~v\times B$ $F = (1.6\times 10^{-19}~C)(6.0 \times 10^6~m/s)(2.50~T)$ $F = 2.4 \times 10^{-12}~N$ By the right hand rule, $v \times B$ is directed vertically upward.
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