Answer
$F = 1.6 \times 10^{-12}~N$
Work Step by Step
We can find the magnetic force:
$F = q~v~B$
$F = (1.6\times 10^{-19}~C)(2.0 \times 10^7~m/s)(0.50~T)$
$F = 1.6 \times 10^{-12}~N$
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